The n-th harmonic number Hn
is defined by
Hn = 1 + 1/2 + 1/3 + ... + 1/n,
so that
H1 = 1,
H2 = 3/2,
H3 = 11/6,
H4 = 25/12,
H5 = 137/60,
H6 = 49/20,
H7 = 363/140,
H8 = 761/280,
H9 = 7129/2520,
and so on.
It turns out that these numbers are well approximated by the natural logarithm. To work out the details, let us write
so thatan =the integral of1/xover the interval(n,n+1),
an < 1/n < an-1
for all n = 1,2,3,... , and so
a1+a2+...+an < Hn <=
1+a1+a2+...+an-1
for all n = 1,2,3,... . Integral calculus tells us that
an = ln (n+1) - ln n,
and so
ln (n+1)
< Hn <=
1 + ln n.
for all n = 1,2,3,... .
One can do better yet. Since
Hn - ln n > Hn - ln (n+1) > 0
and
Hn+1 - ln (n+1) =
(Hn - ln n) + (1/(n+1) - an)
< Hn - ln n
for all n = 1,2,3,... , the sequence
Hn - ln n (n = 1,2,3,...)
is positive and decreasing:
H1 - ln 1 = 1,
H2 - ln 2 = 0.806852...,
H3 - ln 3 = 0.734721...,
H4 - ln 4 = 0.697038...,
H5 - ln 5 = 0.673895...,
H6 - ln 6 = 0.658240...,
H7 - ln 7 = 0.646946...,
H8 - ln 8 = 0.638415...,
H9 - ln 9 = 0.631743...,
and so on. Hence it tends to a limit. This limit is known as the
Euler-Mascheroni
constant, (see the web
page from Eric Weisstein's MathWorld ), it is usually denoted by
gamma, and it equals about 0.577215... . To
summarize, we have
gamma < Hn - ln n <=
1
for all n = 1,2,3,... and the lower bound is
asymptotically tight.