The n
-th harmonic number Hn
is defined by
Hn = 1 + 1/2 + 1/3 + ... + 1/n
,
so that
H1 = 1, H2 = 3/2, H3 = 11/6, H4 = 25/12, H5 = 137/60, H6 = 49/20, H7 = 363/140, H8 = 761/280, H9 = 7129/2520,and so on.
It turns out that these numbers are well approximated by the natural logarithm. To work out the details, let us write
so thatan =
the integral of1/x
over the interval(n,n+1)
,
an < 1/n < an-1
for all n = 1,2,3,...
, and so
a1+a2+...+an < Hn <=
1+a1+a2+...+an-1
for all n = 1,2,3,...
. Integral calculus tells us that
an = ln (n+1) - ln n
,
and so
ln (n+1)
< Hn <=
1 + ln n
.
for all n = 1,2,3,...
.
One can do better yet. Since
Hn - ln n > Hn - ln (n+1) > 0
and
Hn+1 - ln (n+1) =
(Hn - ln n) + (1/(n+1) - an)
< Hn - ln n
for all n = 1,2,3,...
, the sequence
Hn - ln n (n = 1,2,3,...)
is positive and decreasing:
H1 - ln 1 = 1, H2 - ln 2 = 0.806852..., H3 - ln 3 = 0.734721..., H4 - ln 4 = 0.697038..., H5 - ln 5 = 0.673895..., H6 - ln 6 = 0.658240..., H7 - ln 7 = 0.646946..., H8 - ln 8 = 0.638415..., H9 - ln 9 = 0.631743...,and so on. Hence it tends to a limit. This limit is known as the Euler-Mascheroni constant, (see the web page from Eric Weisstein's MathWorld ), it is usually denoted by
gamma
, and it equals about 0.577215...
. To
summarize, we have
gamma < Hn - ln n <=
1
for all n = 1,2,3,...
and the lower bound is
asymptotically tight.